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Determine the value of loga18 if loga2= 0.2789 and loga3= 0.4421

 

I would really appreciate some help!

 Mar 4, 2020
 #1
avatar+22043 
+2

logb(MN)= logb(M)+logb(N).

 

loga( 2*3*3)=   log 2   + log 3  + log 3

     log (18 ) = .2789  + .4421  + .4421=......

 Mar 4, 2020
 #2
avatar+29249 
+4

"Determine the value of loga18 if loga2= 0.2789 and loga3= 0.4421"

 

18 = 2*32 so loga18 = loga(2*32)

 

Using the properties of logarithms we have loga(2*32) = loga2 + loga32 = loga2 + 2*loga3

 Mar 4, 2020

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