Determine the value of loga18 if loga2= 0.2789 and loga3= 0.4421
I would really appreciate some help!
logb(MN)= logb(M)+logb(N).
loga( 2*3*3)= log 2 + log 3 + log 3
log (18 ) = .2789 + .4421 + .4421=......
"Determine the value of loga18 if loga2= 0.2789 and loga3= 0.4421"
18 = 2*32 so loga18 = loga(2*32)
Using the properties of logarithms we have loga(2*32) = loga2 + loga32 = loga2 + 2*loga3
+66 
+36916 
