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The values of x and y are always positive, and x^2 and y vary inversely. If y is 10 when x is 2, then find x when y is 4000.

 May 10, 2022
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y ==1/x^2 * k, where k==constant of proportionality

 

10 ==1/2^2 * k, solve for k

10 ==1/4 * k

k ==40

 

4000 ==1/x^2 * 40

4000/40 ==1/x^2100 ==
100 ==1/x^2, solve for x

 

x ==+or- 1/10

 May 10, 2022

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