The values of x and y are always positive, and x^2 and y vary inversely. If y is 10 when x is 2, then find x when y is 4000.
y ==1/x^2 * k, where k==constant of proportionality
10 ==1/2^2 * k, solve for k
10 ==1/4 * k
k ==40
4000 ==1/x^2 * 40
4000/40 ==1/x^2100 == 100 ==1/x^2, solve for x
x ==+or- 1/10
