Hey, can anyone help solve this proportion? \({5-c\over3}={2c+2\over-4}\), thanks!
+72 We have to get a common denominator in both equations. Let's try to make it positive and the smallest, so it would be 12. Multiplying the left side by 4 would get us (20-4c)/12 and multiplying by -3 on the right side would get us (-6c-6)/12. We can cancel out the denominators by multiply both sides by 1/12 to get 20-4c=-6c-6. Adding 6 to both sides gets us -4c+26=-6c and adding 4c to both sides gets us 26=-2c. Divide by -2 on both sides to get c = -13. Hope this helps!
+72 We have to get a common denominator in both equations. Let's try to make it positive and the smallest, so it would be 12. Multiplying the left side by 4 would get us (20-4c)/12 and multiplying by -3 on the right side would get us (-6c-6)/12. We can cancel out the denominators by multiply both sides by 1/12 to get 20-4c=-6c-6. Adding 6 to both sides gets us -4c+26=-6c and adding 4c to both sides gets us 26=-2c. Divide by -2 on both sides to get c = -13. Hope this helps!
+2863 You can easily solve this by using cross multiplication. To do this, multiply each side by the denominator of the fraction from the opposite side of the equation. When that is done you should have this: -4(5-c)=3(2c+2). Now that it is easy to simplify, we use the distributive property to simplify it to -20+4c=6c+6. Then we will have to move the variables to one side, we do this by subtracting 6c from the right side of the equation. Now we have -20-2c=6, then we add 20, which leads to; -2c=26. We then can divide by negative 2 to completely isolate the variable. This gives us the answer as c=-13.
