Jacinto had a box on the left side and a box on the right side to put balls. He has 50 balls, 8 out of every 4 balls were in the left box. How many balls were in the right box.
8 out of 4 ball is in left side
Now dividing 50 by (8+4) = 12
We get 4.166, Taking only integer part 4
In 4 turns, he will put 32 balls in right side , 16 balls in left side
In fifth turn , he has 2 ball only
Which he will again put in right box
Therefore total balls in right box = 32+2 = 34 balls
The posted question is in a dialect of incompetence. There is no solution as presented; there is no known method for separating “eight out of four balls.”
The presented solution is useless, except as an example of ineptitude.