prove that (3+2√2)^2n-1 + (3-2√2)^2n-1 - 2 is a perfect integral square for every positive integer n.
(3+2√2)^2n-1 + (3-2√2)^2n-1 - 2
\((3+2\sqrt2)^2*n-1 + (3-2\sqrt2)^2*n-1 - 2\\ =n(3+2\sqrt2)^2 + n(3-2\sqrt2)^2-4\\ \)
Is this what you intended to write or do you need brackets anywhere?
+12 
