prove that (3+2√2)^2n-1 + (3-2√2)^2n-1 - 2 is a perfect integral square for every positive integer n.
(3+2√2)^2n-1 + (3-2√2)^2n-1 - 2
(3+2√2)2∗n−1+(3−2√2)2∗n−1−2=n(3+2√2)2+n(3−2√2)2−4
Is this what you intended to write or do you need brackets anywhere?
+12 
