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Answer: 89/245


I have no idea how to approach this.

 Jul 31, 2019

If you look at how many possible 2nd cards satisfy the condtion for a given first card

you'll see there are 2 inital cards each that have 10-19 cards that satisfy it,

and then 30 initial cards that have 20 cards that will satisfy it.


That leads to 


\(p = \dfrac{1}{25}\dfrac{1}{49}\sum \limits_{k=10}^{19}k + \dfrac{30}{50}\dfrac{20}{49}=\dfrac{89}{245}\)

 Jul 31, 2019

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