+0  
 
+1
310
8
avatar+935 

Answer: 119

 

I had no idea how to approach this.

 Jul 31, 2019
edited by dgfgrafgdfge111  Jul 31, 2019
 #1
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+1

Is the answer you posted a wrong or a correct solution?

 Jul 31, 2019
 #2
avatar+110163 
+1

It is correct - At least he believes it to be correct and it probably is.

Melody  Aug 1, 2019
 #3
avatar+110163 
+2

AB is 10 units

10^2=100

You need 2 squared numbers that add or subtract to 100    (pythagoras's theorum)They will be the distances from A to X and B to X

You should be able to take it from there,

 Aug 1, 2019
 #4
avatar+30631 
+3

Approach this by first drawing circles centred on point (-5,0) of radii 1, 2, 3 ... 10.

Then draw circles centred on point (5,0) with the same radii.

At the points where these circles intersect the distance from A is a positive integer less than or equal to 10, as is the distance from B.

It is a simple matter to count these intersection points. There are, indeed, 119 of them.

 Aug 1, 2019
 #5
avatar+110163 
+1

Mmm.

Thanks Alan, seems I oversimplified.  I'll have to take a proper  look. 

Melody  Aug 1, 2019
 #6
avatar+30631 
+3

Here's the picture:

 

Alan  Aug 2, 2019
 #7
avatar+110163 
+1

My goodness. That person has taken way too many psychedelic drugs!

 

Thanks Alan :))

Melody  Aug 2, 2019
 #8
avatar+935 
+1

Wow Alan. Thats .... Interesting? But it is really smart! Thanks!!!

dgfgrafgdfge111  Aug 3, 2019

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