We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
+1
70
2
avatar+893 

Answer: 4

 

I have no idea how to approach this.

 Aug 3, 2019
 #1
avatar+5798 
+2

let the vertices of the triangle be labeled a, b, c, and the midpoints d, e, f

 

let the sum of a given leg equal S

 

3S = 3(a+b+c) + (d+e+f)

 

S = (a+b+c) + (d+e+f)/3

 

Note that n=(d+e+f)/3 is an integer

 

n cannot be 1 as the minimum value is 2

 

if n=2, the only possible values of d, e, f are (1,2,3)

 

if n=3, the possible values of d, e, f are (1,2,6), (1, 3, 5), (2, 3, 4)

 

Setting d, e, and f, fixes what you can use for a, b, and c as any different combos will be rotations or reflections.

 

Thus you have 4 possible ways to arrange the triangle.

 Aug 3, 2019
 #2
avatar+893 
+1

Thanks!!!!

dgfgrafgdfge111  Aug 4, 2019

12 Online Users

avatar
avatar