a+b+c+d+e+f+g+h+i+j+k+l = 24.05
(a+b+c+d+e+f) - (g+h+i+j+k+l) = 6.05
9(a+b+c+d+e+f) / (g+h+i+j+k+l) = 15.05
(a+b+c+g+h+j) - (d+e+f+i+j+l) = 2.95
(a+c+e+g+i+k) - (b+d+f+h+i+j) = 1.95
2(d+e+f+i+j+l) - (a+b+c+g+h+j) = 7.6
abc + def + ghi + jkl = 40.978
(abc + ghi) - (def - jkl) = 19.642
ab + cd + ef + gh + ij + kl = 28.48
(ab + ef + ij) - (cd + gh + kl) = 12.52
(a+b)*(c+d) + (e+f)*(g+h) + (i+j)*(k+l) = 48.45
(a+b)*(c+d) - (e+f)*(g+h) - (i+j)*(k+l) = 8.55
a=? b=? c=? d=? e=? f=? g=? h=? i=? j=? k=? l=?
+118608 1) a+b+c+d+e+f+g+h+i+j+k+l = 24.05
2) (a+b+c+d+e+f) - (g+h+i+j+k+l) = 6.05
3) 9(a+b+c+d+e+f) / (g+h+i+j+k+l) = 15.05
4) (a+b+c+g+h+j) - (d+e+f+i+j+l) = 2.95
5) (a+c+e+g+i+k) - (b+d+f+h+i+j) = 1.95
6) 2(d+e+f+i+j+l) - (a+b+c+g+h+j) = 7.6
7) abc + def + ghi + jkl = 40.978
8) (abc + ghi) - (def - jkl) = 19.642
9) ab + cd + ef + gh + ij + kl = 28.48
10) (ab + ef + ij) - (cd + gh + kl) = 12.52
11) (a+b)*(c+d) + (e+f)*(g+h) + (i+j)*(k+l) = 48.45
12) (a+b)*(c+d) - (e+f)*(g+h) - (i+j)*(k+l) = 8.55
a=? b=? c=? d=? e=? f=? g=? h=? i=? j=? k=? l=?
Let x = a+b+c+d+e+f and y = g+h+i+j+k+l
x+y=24.05 From (1)
x-y=6.05 From (2)
add
2x=30.1
x=15.05
y=24.05-15.05 = 9
so
lets look at (3)
9x/y = 9*15.05/9 = 15.05 so (3) is true and it does not help solve anything.
So we have exhausted all the clues from lines 1,2 and 3 and we have discovered that:
a+b+c+d+e+f = 15.05 and g+h+i+j+k+l = 9
My interest has now wained, maybe I will come back to it later. :)
+319 ╱╱╱╱╱╱╱╱╱╱╱╱╱╱╱
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Credit goes to: MagikalRedNiteTiger
+116 I didn't create the design, so credit actually goes to ACII Text Art.
+2440 Cphill answered this exact question somewhere else on this forum by using the method of completing the square. To view it, click here to redirect you to his solution.
+14913 -2x2-5x=-50
Hello Guest!
\(-2x^2-5x=-50\) [ both sides + 50
\(-2x^2-5x+50=0\) [ : (-2)
\(x^2+\frac{5}{2}x-25=0\)
p q
\(x=-\frac{p}{2}\pm\sqrt{\frac{p^2}{4}-q}\) [ p,q transfer
\(x=-\frac{5}{4}\pm\sqrt{\frac{25}{16}+25}\) [ calculate root
\(x=-\frac{5}{4}\pm\sqrt{26.5625}=-1.25\pm5.15388203202\)
\(x_1=3.90388203202\\ x_2=-6.40388203202\)
!
