Pyramid

I'm not exactly sure what the problem is asking, but I'll but the area in terms of the things we have. 

The volume of the pyramid is 1/3 of the base area mutliplied by the height. 

So we have the area of the pyramid as $\frac{1}{3}[ABCD]h$ where h is the height. We could probably figure out the height by using the paythagorean theorem through the slant height and the diagonal of ABCD!

I hope I answered your question!

Thanks! :)