Pyrmid again

A pyramid with volume 40 cubic inches has a rectangular base. If the length of the base is doubled, the width tripled and the height increased by $50\%$, what is the volume of the new pyramid, in cubic inches?

$\frac{1}{3}lwh=40\\ lwh=120\\~\\ New\;\;volume\;\; =\frac{1}{3}*2l*3w*1.5h\\ =\frac{1}{3}*2*3*1.5*lwh\\ =3lwh\\ =3*120\\ =360\;\;cubic\;\;inches$