what is the value of x if it is a right triangle. The hypotenuse is 2*sqrt(3). One side is (x*sqrt(3))/3, the other is x
[2*sqrt(3)]^2 =[ (x*sqrt(3))/3]^2 + x^2, solve for x
Solve for x:
12 = (4 x^2)/3
12 = (4 x^2)/3 is equivalent to (4 x^2)/3 = 12:
(4 x^2)/3 = 12
Multiply both sides by 3/4:
x^2 = 9
Take the square root of both sides:
Answer: |x = 3 or x = -3
+118629 what is the value of x if it is a right triangle. The hypotenuse is 2*sqrt(3). One side is (x*sqrt(3))/3, the other is x
\(x^2+(\frac{x\sqrt3}{3})^2=(2\sqrt3)^2\\ x^2+(\frac{3x^2}{9})=(4*3)\\ x^2+(\frac{x^2}{3})=12\\ x^2(1+\frac{1}{3})=12\\ x^2=12\div \frac{4}{3}\\ x^2=12\times \frac{3}{4}\\ x^2=9\\ x=3 \qquad \text{x is a distance so it cannot be negative}\)
