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A volleyball is thrown straight up.  The equation that describes its motion is h(t) = -16t^2 + 48t + 4, where h represents the height in feet and t represents time in seconds.  How long will it take for the ball to hit the ground?  Round to the nearest hundredth, if necessary.

Whiz333  Apr 15, 2017
 #1
avatar+90001 
+2

When it hits the ground, h(t)  will = 0  .....so.....

 

0  =  -16t^2 + 48t + 4     divide through by -4

 

0 = 4t^2 -12t -1

 

4t^2 -12t - 1  = 0        

 

Using the quadratic formula....the ball hits the ground at t ≈  3.08 sec

 

 

cool cool cool

CPhill  Apr 16, 2017

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