A volleyball is thrown straight up.  The equation that describes its motion is h(t) = -16t^2 + 48t + 4, where h represents the height in feet and t represents time in seconds.  How long will it take for the ball to hit the ground?  Round to the nearest hundredth, if necessary.

Whiz333  Apr 15, 2017

When it hits the ground, h(t)  will = 0  .....so.....


0  =  -16t^2 + 48t + 4     divide through by -4


0 = 4t^2 -12t -1


4t^2 -12t - 1  = 0        


Using the quadratic formula....the ball hits the ground at t ≈  3.08 sec



cool cool cool

CPhill  Apr 16, 2017

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