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An object is launched at 17.2 m/s from a 25-meter tall platform. The equation for the object's height h at time t seconds after launch is: h(t) = -4.9t^2 + 17.2t +25, where h is in meters. 

a. Graph this equation. 
b. When does the object strike the ground?

Whiz333  Apr 21, 2017
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2+0 Answers

 #1
avatar+26096 
+2

Here's the graph:

 

Set h(t) = 0 and solve using the quadratic equation to find the time at which the object strikes the ground (choose the positive solution!).

Alan  Apr 21, 2017
edited by Alan  Apr 21, 2017
 #2
avatar+76096 
+2

 

Here's the graph : https://www.desmos.com/calculator/afjnvqraph

 

The  object hits the ground after about 4.616 s

 

 

cool cool cool

CPhill  Apr 21, 2017

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