+0

# Quadratic Equation and Inequality Question

0
75
2
+78

Algebraically solve the following inequality and write the solution sets:

-3x2+24x-3 ≤ -3

You can use any method ( Case analysis, test intervals or sign chart )

Jan 25, 2022

#1
+1334
+3

Subtract $$3$$ from both sides:

$$-3x^2+24x \leq 0$$

Factor the equation by $$3x$$:

$$3x(-x+8) \leq 0$$

Both $$3x$$ and $$-x+8$$ have to be less than or equal to $$0$$. This means your answer is $$\color{red}x \leq 0$$ or $$\color {red}x \geq 8$$

Jan 25, 2022
#2
+78
+1

Thank you so much! <3

Jan 25, 2022