+82 Algebraically solve the following inequality and write the solution sets:
-3x2+24x-3 ≤ -3
You can use any method ( Case analysis, test intervals or sign chart )
+2666 Subtract \(3 \) from both sides:
\(-3x^2+24x \leq 0\)
Factor the equation by \(3x\):
\(3x(-x+8) \leq 0\)
Both \(3x\) and \(-x+8\) have to be less than or equal to \(0\). This means your answer is \(\color{red}x \leq 0\) or \(\color {red}x \geq 8\)
