+0  
 
0
75
2
avatar+78 

Algebraically solve the following inequality and write the solution sets:

-3x2+24x-3 ≤ -3

 

You can use any method ( Case analysis, test intervals or sign chart )

 Jan 25, 2022
 #1
avatar+1334 
+3

Subtract \(3 \) from both sides:

\(-3x^2+24x \leq 0\)

Factor the equation by \(3x\):

\(3x(-x+8) \leq 0\)

Both \(3x\) and \(-x+8\) have to be less than or equal to \(0\). This means your answer is \(\color{red}x \leq 0\) or \(\color {red}x \geq 8\)

 Jan 25, 2022
 #2
avatar+78 
+1

Thank you so much! <3

 Jan 25, 2022

26 Online Users

avatar
avatar
avatar