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Find the product of all positive integer values of c such that 8x^2 + 45x + c = 0 has two real roots.

 Sep 8, 2021
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 Find the product of all positive integer values of c.

 

Hallo Guest!

 

\(8x^2 + 45x + c = 0\)

\(x^2+ \frac{45}{8}x+\frac{c}{8}=0\\c<64\)

\(c\in \{1,2..\ ..62,63\}\)

 

The product of all positive integer values of c is  

\(\large 63!= 1.98260383154044401..\)    \(\large ..729600000000000000\times 10^{87}\)

                                                \(88\ decimal\ digits\)

laugh  !

 Sep 8, 2021
edited by asinus  Sep 8, 2021
edited by asinus  Sep 8, 2021
edited by asinus  Sep 8, 2021
edited by asinus  Sep 8, 2021

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