Find the product of all positive integer values of c such that 8x^2 + 45x + c = 0 has two real roots.
Find the product of all positive integer values of c.
Hallo Guest!
\(8x^2 + 45x + c = 0\)
\(x^2+ \frac{45}{8}x+\frac{c}{8}=0\\c<64\)
\(c\in \{1,2..\ ..62,63\}\)
The product of all positive integer values of c is
\(\large 63!= 1.98260383154044401..\) \(\large ..729600000000000000\times 10^{87}\)
\(88\ decimal\ digits\)
!