Let the roots of the polynomial $x^2 + 7x - 2$ be $\alpha$ and $\beta.$ Evaluate $\alpha^2 \beta^2.$
\(\alpha^2 \beta^2\)
1x^2 + 7x - 2
By Viete :
In a polynomial of the form ax^2 + bx + c, the product of the roots = c / a
Product of the roots = alpha * beta = c/a = -2/1 = -2 square both sides
(alpha * beta)^2 = (-2)^2
alpha^2* beta^2 = 4
+816 
