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The function f(t) = 50(1.07)^t models the growth of a fly population, where f(t) is the number of flies and t is time in days.  After three weeks, approximately how many flies are in the population? Show your solution.

Whiz333  Apr 20, 2017
 #1
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3 weeks  = 21 days.....so

 

50(1.07)^21  = about 207 flies

 

 

cool cool cool

CPhill  Apr 20, 2017

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