+0

+1
52
1
+300

If the roots of the quadratic equation $\frac12x^2+99x+c=0$ are $x=-99+\sqrt{8001}$ and $x=-99-\sqrt{8001}$, then what is the value of c?

Feb 22, 2021

#1
+204
0

When using the quadratic formula, you can look in the square root and that is 9801-2c. So you take the 8001 from the problem and subtract it from 9801 and you get 1800. Then you divide 1800 in half getting 900 which is your answer.

Feb 22, 2021