+0  
 
0
677
2
avatar+78 

Consider x^2 + px + q = 0, where p and q are rational numbers. If one root of this equation is (radical 5) + 2, then the value o f p + q equals...

A. -5

B. -1

C. -2

E. 0

 

Thank you for helping! :D

 Jul 18, 2020
 #1
avatar+37153 
+2

2 + sqrt5       the other root would be    2 - sqrt5

 

SO the quadratic factored loks like this:

(x - (2+sqrt5) )(x-(2-sqrt5) )       if you multiply this out

x^2 -4x-1         now you can add   p  and  q

 Jul 18, 2020
 #2
avatar+78 
0

Oh, I see! Thank you for helping me :D

Frooglie  Jul 18, 2020

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