+33616 When you have a quadratic equation in the form: \(ax^2+bx+c=0\)
the two solutions are given by: \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
In your case:
A) a = 5, b = 7 and c = 2 (because it can be rewritten as 5x2 + 7x + 2 = 0
B) a = 12, b = -28 and c = 15
Plug these values into the formula above.
.
+33616 When you have a quadratic equation in the form: \(ax^2+bx+c=0\)
the two solutions are given by: \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
In your case:
A) a = 5, b = 7 and c = 2 (because it can be rewritten as 5x2 + 7x + 2 = 0
B) a = 12, b = -28 and c = 15
Plug these values into the formula above.
.
