The height of a baseball t seconds after it is hit up in the air is given by h=-9t^{2}+52t+3. What is the maximum height of the ball?

I also need to know:

What is the y-intercept of the ball's path in the problem above AND what is its meaning in the problem?

How long was the ball in the air in the problem above?

Guest Jan 4, 2019

edited by
Guest
Jan 4, 2019

#1**+3 **

"*The height of a baseball t seconds after it is hit up in the air is given by h=-9t2+52t+3. What is the maximum height of the ball?*

*I also need to know:*

*What is the y-intercept of the ball's path in the problem above AND what is its meaning in the problem?*

*How long was the ball in the air in the problem above?*"

Alan Jan 4, 2019

#2**+2 **

Max height t is also given by -b/2a of the quadratic equation> -52/(-18) = t = 2.889 sec

h(max) = -9 (2.889)^2 + 52(2.889) + 3 = 78.11 (feet?)

Y intercept is initial height of ball when t = 0 -9(0^2) +52(0) +3 = 3 (feet?)

As Alan showed, time in the air ends when h= 0 0 = -9(t^2)+52t+3 Using Quadratic Equation t = 5.835 sec

ElectricPavlov Jan 4, 2019