What is the value of b + cif x^2 + bx + c > 0 if only when $x \in (-\infty,2) \cup (3,\infty)$?
+204 From https://web2.0calc.com/questions/what-is-the-value-of-b-c-if-x-2-bx-c-gt-0-only-when
What is the value of
\(\text{b+c if }\;\;x^2+bx+c>0\qquad \text{only when }\;\;x\in (-\infty, -2)\cup(3,\infty)?\)
Well that means that y cannot not be positive for x in [-2,3]
So the roots are x=-2 and x=3 and it is concave up
so the expression is
\((x+2)(x-3) = x^2-x-6\)
You can do the addition.
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