I keep trying, but I can't get this.
The two solutions of the equation x^2 + bx + 18 = 0 are in the ratio of 3 to 1 for some values of b. What is the largest possible value of b?
Hm.. can you explain further for the 3:1 ratio is it for the variable b or the variable x?
I get it now. Okay so first, look at the constant term 18. we need some 2 numbers to be in a 3:1 ratio and multiply to get 18 so
xy=18
4y=x
from this system of equations we get
y=√4.5
x=√72
these are the 2 solutions the this quadratic.
we can express this as
(x−√4.5)(x−√72)=0
so b is equal to √4.5+√72
hope this helped(i hope this is not wrong)