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The equation y = -16t^2 + 28t + 180 describes the height (in feet) of a ball tossed up in the air at 28 feet per second from a height of 180 feet from the ground. In how many seconds will the ball hit the ground?

Feb 7, 2021

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+11086
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The equation y = -16t^2 + 28t + 180 describes the height (in feet) of a ball tossed up in the air at 28 feet per second from a height of 180 feet from the ground. In how many seconds will the ball hit the ground?

Hello Guest!

$$vt-\dfrac{g}{2}t^2=-180\\ \dfrac{28ft}{s}\cdot t-\dfrac{9.80716.087m}{2\cdot sec^2}\cdot \dfrac{ft}{0,3048037064m}\cdot t^2+180ft=0\\ 28t-16.0874t^2+180=0$$

$$t=4,326575159634674\ s$$

In 4.32 seconds will the ball hit the ground.

!

Feb 8, 2021