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Let $(x) = ax^2 + bx + 18 be a quadratic polynomial. If the minimum value of f(x) = 6 when x = \(4\), find a + b.

 Feb 1, 2022
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We know the minimum of this bowl shaped ( if a is positive value) parabola will occur at x = - b/2a 

       so      4 = - b/2a

 

and the value at x = 4   is 6 

           16 a  + 4b + 18 = 6             Now you have two equations and two unknowns.....can you solve for a and b from here ?

 Feb 1, 2022

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