Find the non-zero value of $a$ such that the quadratic equation $ax^2+8x+4=6x-40$ has only one solution.

bingboy Sep 11, 2023

#2**+1 **

CPhill made just a slight error :

Re-write as ax^2 + 2x + __ 46 __ = 0 Should be ax^2 + 2x +

Then following through with his calculations will show a = 4/ 176 = ** 1/44 **

ElectricPavlov Sep 11, 2023

#1**+1 **

Re-write as ax^2 + 2x + 46 = 0

If we only have one solution , the discriminant = 0

So

2^2 - 4(a) (46) = 0

4 - 184a = 0

4 = 184a

a = 4/184 = 1 / 46

CPhill Sep 11, 2023

#2**+1 **

Best Answer

CPhill made just a slight error :

Re-write as ax^2 + 2x + __ 46 __ = 0 Should be ax^2 + 2x +

Then following through with his calculations will show a = 4/ 176 = ** 1/44 **

ElectricPavlov Sep 11, 2023