+743 Find the non-zero value of $a$ such that the quadratic equation $ax^2+8x+4=6x-40$ has only one solution.
+37146 CPhill made just a slight error :
Re-write as ax^2 + 2x + 46 = 0 Should be ax^2 + 2x + 44
Then following through with his calculations will show a = 4/ 176 = 1/44
+129845 Re-write as ax^2 + 2x + 46 = 0
If we only have one solution , the discriminant = 0
So
2^2 - 4(a) (46) = 0
4 - 184a = 0
4 = 184a
a = 4/184 = 1 / 46
+37146 CPhill made just a slight error :
Re-write as ax^2 + 2x + 46 = 0 Should be ax^2 + 2x + 44
Then following through with his calculations will show a = 4/ 176 = 1/44
