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For what value of b will this equation have only one real root: (2b−5)x^2−2(b−1)x+3=0.

 Oct 3, 2020
 #1
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The discriminant of the quadratic formula must = 0 to have only one root

b^2 - 4ac = 0

 

b in the quadratic formula for this case is -2b+2      a is 2b-5     c is 3  

 

Plug these values into the red equation to find  b = 4

 Oct 3, 2020
 #2
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For what value of b will this equation have only one real root: (2b−5)x^2−2(b−1)x+3=0.

laugh

 Oct 3, 2020

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