The graph of a certain quadratic y = ax^2 + bx + c is a parabola with vertex (-4,0) which passes through the point (1,-7). What is the value of a?

Guest Jun 27, 2022

#1**0 **

Recall vertex form: \(a(x-h)^2 + k = y\)

Substituting the vertex, we have: \(a(x + 4)^2 = y\)

Plugging in the point, we have: \(25a = -7\).

Can you take it from here?

BuilderBoi Jun 27, 2022

#1**0 **

Best Answer

Recall vertex form: \(a(x-h)^2 + k = y\)

Substituting the vertex, we have: \(a(x + 4)^2 = y\)

Plugging in the point, we have: \(25a = -7\).

Can you take it from here?

BuilderBoi Jun 27, 2022