The graph of a certain quadratic y = ax^2 + bx + c is a parabola with vertex (-4,0) which passes through the point (1,-7). What is the value of a?
Recall vertex form: \(a(x-h)^2 + k = y\)
Substituting the vertex, we have: \(a(x + 4)^2 = y\)
Plugging in the point, we have: \(25a = -7\).
Can you take it from here?