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The graph of a certain quadratic y = ax^2 + bx + c is a parabola with vertex (-4,0) which passes through the point (1,-7). What is the value of a?

 Jun 27, 2022

Best Answer 

 #1
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Recall vertex form: \(a(x-h)^2 + k = y\)

 

Substituting the vertex, we have: \(a(x + 4)^2 = y\)

 

Plugging in the point, we have: \(25a = -7\).

 

Can you take it from here?

 Jun 27, 2022
edited by BuilderBoi  Jun 27, 2022
 #1
avatar+2222 
0
Best Answer

Recall vertex form: \(a(x-h)^2 + k = y\)

 

Substituting the vertex, we have: \(a(x + 4)^2 = y\)

 

Plugging in the point, we have: \(25a = -7\).

 

Can you take it from here?

BuilderBoi Jun 27, 2022
edited by BuilderBoi  Jun 27, 2022

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