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Find the product of all positive integer values of c such that  8x^2 - 13x + c = 0 has two real roots.

Oct 7, 2020

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Find C such that 8x^2 - 13x + c = 0 has two real roots.

Hello Guest!

$$8x^2-13x+c=0$$

$$\large x = {-b \pm \sqrt{b^2-4ac} \over 2a}$$

$$b^2> 4ac\\ 169> 32c\\ \color{blue}c\in\{0,1,2,3,4,5\}$$

The product of all positive integer values of c such

that 8x^2 - 13x + c = 0 has two real roots is 120.

!

Oct 7, 2020
edited by asinus  Oct 7, 2020