Find the product of all positive integer values of c such that 8x^2 - 13x + c = 0 has two real roots.
+14901 Find C such that 8x^2 - 13x + c = 0 has two real roots.
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\(8x^2-13x+c=0\)
\(\large x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(b^2> 4ac\\ 169> 32c\\ \color{blue}c\in\{0,1,2,3,4,5\}\)
The product of all positive integer values of c such
that 8x^2 - 13x + c = 0 has two real roots is 120.
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