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The equation y = -6t^2 + 51t describes the height (in feet) of a projectile launched from the surface of Mars at 51 feet per second. In how many seconds will the projectile first reach 118 feet in height?

 Jul 24, 2021
 #1
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-6t^2  + 51t =  118

 

-6t^2  +  51t   - 118 =   0                     multiply through by   -1

 

6t^2   - 51t  +  118  =   0

 

The discriminant  =      51^2  - 4*6 * 118    =   -231

 

So......this never occurs....see  the  graph here  :  https://www.desmos.com/calculator/nbovxklqyd

 

The max height reached is ≈  108 ft

 

 

cool cool cool

 Jul 24, 2021

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