The quadratic equation ax^2 + 8x + c = 0 has exactly one solution. If a + c = 12, and a < c, find the ordered pair (a, c).
+2094 Hint: Here are the possible values of a and c. Try plugging them in and solving it.
a=5, c=7
a=4, c=8
a=3, c=9
a=2, c=10
a=1, c=11
Tell me if you need more help :)
+36916 For one solution thie discriminant of the quadratic = 0 b^2 - 4ac = 0
64 - 4 ac = 0
so another equation relating a and c 64 - 4 ac = ac = 16 and given c = 12-a
a (12-a) = 16
-a^2 + 12a - 16 = 0 quadratic formula shows a = 6 - 2sqrt 5
and c = 6 + 2 sqrt 5
+2094 For future uses, the quadratic formula is:
\(\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)
