+0  
 
0
114
1
avatar

The equation y = -6t^2 + 51t describes the height (in feet) of a projectile launched from the surface of Mars at 51 feet per second. In how many seconds will the projectile first reach 100 feet in height?

 Feb 4, 2022
 #1
avatar+36435 
+1

100 = -6t^2 + 51t

 

-6t^2 + 51 t  - 100 = 0       use Quadratic Fromula to find the values of 't' where the height = 100   

                                           the smaller 't' will be the first time the object hits 100 ft

 

a = -6       b = 51        c = -100

\(t = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

 Feb 4, 2022

25 Online Users