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The equation y = -6t^2 + 51t describes the height (in feet) of a projectile launched from the surface of Mars at 51 feet per second. In how many seconds will the projectile first reach 100 feet in height?

Feb 4, 2022

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100 = -6t^2 + 51t

-6t^2 + 51 t  - 100 = 0       use Quadratic Fromula to find the values of 't' where the height = 100

the smaller 't' will be the first time the object hits 100 ft

a = -6       b = 51        c = -100

$$t = {-b \pm \sqrt{b^2-4ac} \over 2a}$$

Feb 4, 2022