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The equation y = -16t^2 + 26t + 105 describes the height (in feet) of a ball tossed up in the air at 26 feet per second from a height of 105 feet above the ground. In how many seconds will the ball reach 110 feet? Express your answer as a decimal rounded to the nearest tenth.

 Jul 11, 2021
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110 = - 16t^2 + 26t + 105

-16t^2 +26t -5 = 0      Use Quadratic fromula with a = -16      b = 26     c = -5     to solve for two values of t    the lower one will be for the

                                                ball  on the way up..... the larger represents the time when the ball is on the way down.

 Jul 11, 2021

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