The equation y = -16t^2 + 26t + 105 describes the height (in feet) of a ball tossed up in the air at 26 feet per second from a height of 105 feet above the ground. In how many seconds will the ball reach 110 feet? Express your answer as a decimal rounded to the nearest tenth.
+36915 110 = - 16t^2 + 26t + 105
-16t^2 +26t -5 = 0 Use Quadratic fromula with a = -16 b = 26 c = -5 to solve for two values of t the lower one will be for the
ball on the way up..... the larger represents the time when the ball is on the way down.
