There is exactly one value of $x$ for which the distance from $(5,6)$ to $(3x-1,ax+5)$ is $4$. If $a \neq 0,$ what is $a$?
What is a?
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(x−52)2+(y−6)2=42y=3x−1(x−52)2+(3x−1−6)2=42x2−10x+25+9x2−42x+49−16=010x2−52x+58=0x2−5.2+5.8=0x1,2=2.6±√2.62−5.8x∈{1.620,3.580}
y∈{3.861,9.739}P2 (3.580,9.739)P1 (0,5)a=y2−y1x2−x1=9.739−53.58−0a=1.324
a is 1.324
With P3 (1.620,3.861) the further a can be calculated.
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