quadratic

I interpreted this question as follows:

What is a?

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$(x-5^2)^2+(y-6)^2=4^2\\ y=3x-1\\ (x-5^2)^2+(3x-1-6)^2=4^2\\ x^2-10x+25+9x^2-42x+49-16=0\\ 10x^2-52x+58=0\\ x^2-5.2+5.8=0\\ x_{1,2}=2.6\pm\sqrt{2.6^2-5.8}\\ x\in \{1.620,\color{blue}3.580\}$

$y\in \{3.861,\color{blue}9.739\}\\ P_2\ (3.580,9.739)\\ P_1\ (0,5)\\ a= \dfrac{y_2-y_1}{x_2-x_1}=\dfrac{9.739-5}{3.58-0}\\a=1.324$

$\color{blue}a\ is\ 1.324$

With P3 (1.620,3.861) the further a can be calculated.

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