Wilma and Greg were trying to solve the quadratic equation x^2 + bx + c = 0.Wilma wrote down the wrong value of b (but her value of c was correct), and found the roots to be 1 and 8. Greg wrote down the wrong value of c (but his value of b was correct), and found the roots to be 1 and -4. What are the actual roots of x^2 + bx + c = 0?
+240 Start off with Wilma's equation. We can use Vieta's to find that c/a = 8*1, so c = 8.
Next Greg's equation. Using Vieta's again we can find that -b/a = -4+1 = 3
So piecing it together, the actual equation is,
\(x^2+3x+8\)
Apply quadratic formula to find the roots\(x=−1.5±\frac{\sqrt{23}i}{2}\)
+373 Hey there, Guest!
Greg: (x+1)(x+4) = x^2 + 5x + 5 \(c≠5 \)
Wilma: (x-1)(x-6) = x^2 -7x + 6.
Equation: \((x+3)(x+2) \)
Therefore the roots are -3 & -2.
Hope this helped! :)
( ﾟдﾟ)つ Bye
