The equation y = -16^2 + 26t + 105 describes the height (in feet) of a ball tossed up in the air at 26 feet per second from a height of 105 above the ground. In how many seconds will the ball hit the ground? express your answer as a decimal rounded to the nearest tenth.
We can use the quadratic formula: t = (16 \pm sqrt(26^2 - 4*16*105))/2 = 4.8
So the ball hits the ground in 4.8 seconds.