We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
648
6
avatar+61 

 May 11, 2015

Best Answer 

 #5
avatar+109 
+12

Thanks Melody, I appreciate your support :) 

 

However, I do not like to do the homework for other people. Helping is fine tough. If someone asks a short question, he or she gets probably a short answer back 

 May 11, 2015
 #1
avatar+109 
+7

$${\mathtt{AG}} = {\sqrt{{{\mathtt{2}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{6}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{8}}}^{{\mathtt{2}}}}}$$

 

 

Please mark this post as "answer" if it helped you! 

 May 11, 2015
 #2
avatar+61 
+5

Thanks, how do I post this as answer?

 May 11, 2015
 #3
avatar+109 
-1

I don't know, but there must be a way. I never posted a question. 

 

Some people obviously disagree with me answer. Can someone please state why?

 May 11, 2015
 #4
avatar+100169 
+8

 

Triangle EGH is a right angled triangle.  EG is the hypotenuse.   SO

 

$$EG=\sqrt{6^2+8^2}=\sqrt{100}=10cm$$

 

Now triangle AEG is a right angled triangle and  AG is the hypotenuse

so

$$\\AG=\sqrt{10^2+2^2}=\sqrt{104}=\sqrt{4*26}=2\sqrt{26}cm\\
AG\approx 10.2cm\qquad $correct to 2 decimal places$$$

 

Lets compare this to xerxes's answer.

$$\\AG^2=AE^2+EG^2\\
\\AG^2=2^2+\left(\sqrt{(EH^2+HG^2}\right)^2\\
\\AG^2=2^2+(EH^2+HG^2)\\
\\AG^2=2^2+(8^2+6^2)\\
\\AG^2=2^2+8^2+6^2\\
\\AG=\sqrt{2^2+8^2+6^2}\\$$

 

So you see, Xerxes wass correct in the fist place.  Maybe he should have explained him/herself better but I think he should get positive points not negative ones.

I only have 3 points that i can give you, I am sorry that i cannot give you any more.  :)

 May 11, 2015
 #5
avatar+109 
+12
Best Answer

Thanks Melody, I appreciate your support :) 

 

However, I do not like to do the homework for other people. Helping is fine tough. If someone asks a short question, he or she gets probably a short answer back 

xerxes May 11, 2015
 #6
avatar+100169 
+8

Thanks you xerxes for answering questions and for getting so involved in the forum :)

 

I take your point but you did not give a hint on how to do the question.  

 

You gave a final answer that I do not think any student could have learned from.  

 

I really like it when people give hints without giving an answer but giving an answer without any explanation is usually pretty pointless.

 May 11, 2015

4 Online Users