+312 A PE class has 12 students, 6 girls and 6 boys. The coach has 4 jerseys in each of 3 colors to mark 3 teams for a soccer tournament. If the coach wants at least one girl and at least one boy on each team, how many ways can he give out the jerseys? (Jerseys of the same color are indistinguishable.)
+312 NVM I found 2 ways to do it(My dad helped me, we talked about it all through supper.
)
The way I used was just countnig, not cpunting the opisite and then subtracting.
Boys:
1.) 3 2 1 = 360
2.) 2 2 2 = 90
Girls:
1.) 1 2 3 = 60
2.) 2 2 2 = 90
(Each number is how many people in each group, and then I used combinintry.)
360 x 60 + 90 x 90 = 29700 ways!
The other way is solving they ways that DON'T work. I'm not going to explain it but I can put a screenshot of their explantion.
- WillBill
+2407 BBG BBG BGG BGG is our only way of splitting it up.
To make our groups, 6!*6!/2/2/2/2, but since some groups are the same, 6!*6!/2/2/2/2/2/2 = 8100.
8100 ways of making groups, 4*3*2 of giving colours.
8100*4*3*2 = 194400
Edit:
I read the question wrong, it's 3 groups of 4, not 4 groups of 3.
=^._.^=
