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A square $DEFG$ varies inside equilateral triangle $ABC,$ so that $E$ always lies on side $\overline{AB},$ $F$ always lies on side $\overline{BC},$ and $G$ always lies on side $\overline{AC}.$ The point $D$ starts on side $\overline{AB},$ and ends on side $\overline{AC}.$ The diagram below shows the initial position of square $DEFG,$ an intermediate position, and the final position.

 

Show that as square $DEFG$ varies, the height of point $D$ above $\overline{BC}$ remains constant.

Guest Mar 15, 2018
edited by Guest  Mar 15, 2018
 #1
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Here is the diagram

Guest Mar 15, 2018
 #2
avatar+20024 
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A square $DEFG$ varies inside equilateral triangle $ABC,$ so that $E$ always lies on side $\overline{AB},$ $F$ always lies on side $\overline{BC},$ and $G$ always lies on side $\overline{AC}.$ The point $D$ starts on side $\overline{AB},$ and ends on side $\overline{AC}.$ The diagram below shows the initial position of square $DEFG,$ an intermediate position, and the final position.

 

Show that as square $DEFG$ varies, the height of point $D$ above $\overline{BC}$ remains constant.

 

 

 

see link: https://web2.0calc.com/questions/a-square-defg-varies-inside-equilateral-triangle

 

 

laugh

heureka  Mar 15, 2018
 #4
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I am still confused.

Guest Mar 15, 2018
 #3
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I still don’t get it.

Guest Mar 15, 2018

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