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One-fifth of the sum of two consecutive integers is 64 less than the smaller integer. 
Find the smaller of the two integers.

 Dec 11, 2018
 #1
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Let the smallet integer = S
The larger integer = S + 1
1/5[S + S + 1] =S - 64, solve for S
S = 107 - the smaller integer
107 + 1 =108 - the larger integer

 Dec 11, 2018
 #2
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Thanks!

MobiusLoops  Dec 12, 2018

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