So i was solving a polynomial equation of degree 3, using algaebra.
here is the equation \(2x+3x^2+4x^3=0\) and i arrived to the final as x=0 is the only possible solution. Am i correct?
It has 3 roots:
x=0
x= -1/8 i (sqrt(23)-3 i)
x= 1/8 i (sqrt(23)+3 i)
ok thanks
Yes,the equation has no real roots.When you factor out x to get a quadratic,the discriminant of this quadratic is 9-32 = -23. It's got 2 complex roots,but
I'm assuming you haven't studied complex numbers yet.
