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How many ways are there to put 6 balls in 3 boxes if the balls are not distinguishable but the boxes are?

 Jun 19, 2019
 #1
avatar+1015 
0

Heres 1 way 

 

Way 1= put 2 balls in 1 box*3    

 

So I'm thinking 1 way! 

 

cheekycheekycheeky

 Jun 19, 2019
 #2
avatar+111401 
+1

Assuming we can have empty boxes.....the ways of distributing k indistinguishable balls into n distiguishable boxes  is given by

 

C ( k + n - 1 , n - 1)   =

 

C (6 + 3 - 1, 3 - 1)  =

 

C (8,2)  =

 

28 ways

 

 

cool cool cool

 Jun 19, 2019

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