How many ways are there to put 6 balls in 3 boxes if the balls are not distinguishable but the boxes are?
Heres 1 way
Way 1= put 2 balls in 1 box*3
So I'm thinking 1 way!
Assuming we can have empty boxes.....the ways of distributing k indistinguishable balls into n distiguishable boxes is given by
C ( k + n - 1 , n - 1) =
C (6 + 3 - 1, 3 - 1) =
C (8,2) =
28 ways
