How many ways are there to put 6 balls in 3 boxes if the balls are not distinguishable but the boxes are?

Heres 1 way

Way 1= put 2 balls in 1 box*3

So I'm thinking 1 way!

Assuming we can have empty boxes.....the ways of distributing k indistinguishable balls into n distiguishable boxes is given by

C ( k + n - 1 , n - 1) =

C (6 + 3 - 1, 3 - 1) =

C (8,2) =

28 ways