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3^-8(3^5) could you please help me with this?

 Sep 19, 2017
 #1
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The original expression is \(3^{-8}*3^5\). In order to do this, we can use the fact that the base of both exponents are the same and then simplify.

 

\(3^{-8}*3^5\) Since the bases are identical, just add the exponents together. In general, \(a^b*a^c=a^{b+c}\)
\(3^{-8}*3^5=3^{-8+5}=3^{-3}\) A number to a negative exponent is the same as the inverse of a number to the same positive exponent. \(a^{-b}=\frac{1}{a^b}\)
\(3^{-3}=\frac{1}{3^3}=\frac{1}{3*3*3}=\frac{1}{27}\) This is your answer.
   
 Sep 19, 2017

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