+0  
 
0
167
1
avatar

3^-8(3^5) could you please help me with this?

Guest Sep 19, 2017
 #1
avatar+2075 
0

The original expression is \(3^{-8}*3^5\). In order to do this, we can use the fact that the base of both exponents are the same and then simplify.

 

\(3^{-8}*3^5\) Since the bases are identical, just add the exponents together. In general, \(a^b*a^c=a^{b+c}\)
\(3^{-8}*3^5=3^{-8+5}=3^{-3}\) A number to a negative exponent is the same as the inverse of a number to the same positive exponent. \(a^{-b}=\frac{1}{a^b}\)
\(3^{-3}=\frac{1}{3^3}=\frac{1}{3*3*3}=\frac{1}{27}\) This is your answer.
   
TheXSquaredFactor  Sep 19, 2017

11 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.