A tire company is selling two different tread patterns of tires. Tire x sells for $75.00 and tire y sells for $85.00.Three times the number of tire y sold must be less than or equal to twice the number of x tires sold. The company has at most 300 tires to sell.

What is the maximum revenue that the company can make?






Guest Sep 19, 2017

1+0 Answers


We can solve this with a graph [ linear programming ]


Let x  = number of  $75 tires to be sold and y  = the number of $ 85 tires to be sold


Here are the constraints to be graphed :


x + y ≤ 300 


3y ≤ 2x


And the objective function to be maximized is this


75x +  85y


A look at the graph here : https://www.desmos.com/calculator/5dtkxwrxak  will show that the max occurs at the corner points of the intersection of the two inequalities


There is only one corner point at  ( x , y)  = (180, 120)


Putting this into the objective function produces


75(180) + 85 (120)  = $ 23700



cool cool cool

CPhill  Sep 19, 2017

3 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details