A tire company is selling two different tread patterns of tires. Tire x sells for $75.00 and tire y sells for $85.00.Three times the number of tire y sold must be less than or equal to twice the number of x tires sold. The company has at most 300 tires to sell.

What is the maximum revenue that the company can make?

$13,500

$22,500

$23,700

$25,500

Guest Sep 19, 2017

#1**+1 **

We can solve this with a graph [ linear programming ]

Let x = number of $75 tires to be sold and y = the number of $ 85 tires to be sold

Here are the constraints to be graphed :

x + y ≤ 300

3y ≤ 2x

And the objective function to be maximized is this

75x + 85y

A look at the graph here : https://www.desmos.com/calculator/5dtkxwrxak will show that the max occurs at the corner points of the intersection of the two inequalities

There is only one corner point at ( x , y) = (180, 120)

Putting this into the objective function produces

75(180) + 85 (120) = $ 23700

CPhill
Sep 19, 2017