+163 So I have sin(arcsin(5/4))...
how do I find the other terminal point for 5/4
for instance the terminal point for sin(pi/6) = sqrt3/2 and cos(pi/6) 1/2
I feel like I'm missing something odvious
+118680 I thinhk you are totally confused and have seriously stuffed up this question.
I will discuss it though.
sin(arcsin(5/4))
arc sin cannot be greater than 1 so I will change the expression.......
sin(arcsin(4/5)) there is only one answer, 4/5
Lets look at your second part and see if that makes more sense
sin(pi/6) = 1/2 (not sqrt3/2) and cos(pi/6) =sqrt3/2 (not 1/2)
I just draw the right angled triangle and also when necessary think about the sign
You don't have a terminal point for the sin of an angle
You have a terminal point on the unit circle for an angle.
the terminal point for pi/6 is ((sqrt3)/2 , 0.5)
+163 thanks, I feel like I expressed this question incorrectly lol
going to restart the question thank you
