If you differente \(y=2x^2+4\)
you get 4x so \(\frac{dy}{dx}\) of \(y=2x^2+4\)
is \(4x\) But if you do \(\frac{d^2y}{dx^2}\)
do you just square the orginial differentation? or do you square \(y=2x^2+4\) then differentiate? Please help!
Thank you very much!
d2y / dx2 is the notation for the second derivative .....many times this is written as ... y "....it is the derivative of the first derivative
So
y " of 4x = 4
No prob, Misaki !!!!
Misaki, I made a slight error in the explanation...I meant to say that :
y" of y = 2x^2 + 4 = 4
It's ok i still understood you!
+129852 
