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If sinA=-.4382. 0<A<360. Find two possible values for A.

 Mar 15, 2017
 #1
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Arcsin  -  .4382 =  334.01 degrees      205.98 degrees

 Mar 15, 2017
edited by ElectricPavlov  Mar 15, 2017
 #2
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If sin(A) = -0.4382.  0 < A < 360.

Find two possible values for A.

 

sin(A)=0.4382A1=arcsin(0.4382)+z360|zZA1=25.9890903445+z360A1=25.9890903445+360+z360A1=334.010909656+z360sin(A)=sin(180A)=0.4382180A2=arcsin(0.4382)+z360|zZA2=180arcsin(0.4382)+z360A2=180(25.9890903445)+z360A2=180+25.9890903445)+z360A2=205.989090344+z360

 

0 < A < 360.

A1=334.010909656A2=205.989090344

 

laugh

 Mar 15, 2017

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