If sin(A) = -0.4382. 0 < A < 360.
Find two possible values for A.
sin(A)=−0.4382A1=arcsin(−0.4382)+z⋅360∘|z∈ZA1=−25.9890903445∘+z⋅360∘A1=−25.9890903445∘+360∘+z⋅360∘A1=334.010909656∘+z⋅360∘sin(A)=sin(180∘−A)=−0.4382180∘−A2=arcsin(−0.4382)+z⋅360∘|z∈ZA2=180∘−arcsin(−0.4382)+z⋅360∘A2=180∘−(−25.9890903445∘)+z⋅360∘A2=180∘+25.9890903445∘)+z⋅360∘A2=205.989090344∘+z⋅360∘
0 < A < 360.
A1=334.010909656∘A2=205.989090344∘