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r(x) has domain {-1,0,1,2} and range {0,2,4,6}. s(x) has domain {1,2,3,4} and is defined by s(x)=x+1. What is the sum of all possible values of s(r(x))?

WhichWitchIsWhich  Nov 5, 2017

Best Answer 

 #1
avatar+7089 
+1

r(x)  has domain  {-1,0,1,2}  and range  {0,2,4,6} .

s(x)  has domain  {1,2,3,4}  and is defined by  s(x) = x + 1.

 

The possible values of r(x)  are  0, 2, 4, and  6 .

 

Of these, only  2  and  4  are "valid" inputs into  s(x)  ....they are the only ones in the domain of s(x) .

 

So we can have  s(2)  and  s(4) .

 

s(2)  =  2 + 1  =  3

 

s(4)  =  4 + 1  =  5

 

So the possible values of  s( r(x) )  are  3  and  5 .

 

3 + 5  =  8      smiley

hectictar  Nov 5, 2017
 #1
avatar+7089 
+1
Best Answer

r(x)  has domain  {-1,0,1,2}  and range  {0,2,4,6} .

s(x)  has domain  {1,2,3,4}  and is defined by  s(x) = x + 1.

 

The possible values of r(x)  are  0, 2, 4, and  6 .

 

Of these, only  2  and  4  are "valid" inputs into  s(x)  ....they are the only ones in the domain of s(x) .

 

So we can have  s(2)  and  s(4) .

 

s(2)  =  2 + 1  =  3

 

s(4)  =  4 + 1  =  5

 

So the possible values of  s( r(x) )  are  3  and  5 .

 

3 + 5  =  8      smiley

hectictar  Nov 5, 2017

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