A buisinessman put 4 different cheques into 4 different envelopes. What is the probability that he gets exactly one incorrect?
4*1/4*2/3*1/2*1=1/3 Maybe
I said the prob that the first one is right is 1/4
The prob that the 2nd is wrong is 2/3
The prob that the 3rd is wrong is 1/2
The prob that the last one is wrong is 1
BUT
it could be the 1st or 2nd or 3rd or 4th that is right so i multiplied by 4
I won't guarantee that it is correct but it sounds ok to me. :)
There are 24 possiible arrangements.......
Let's look at the possible arrangements with cheque 1 going into envelope 1.
So we have
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
Note that only 2 of these have cheque 1 going into envelope 1 and all the others the wrong ones. These would be 1 3 4 2 and 1 4 2 3. So, that is 1/3 of the possible arrangements where cheque 1 goes into envelope 1.
And every other arrangement (2nd check in 2nd envelope, etc.) would have the sme probabilty.
So, the answer - I think - is 1/3.......